Watts to VA Calculator
Convert real power in watts to apparent power in VA using power factor. Clarifies W vs VA for sizing breakers and transformers. Try it free.
Trust summary CVP VERIFIED · CVP protocol 1.0.0-proposed · Engineering assurance
- Input interpretation
- Enter values to calculate.
- Result
- —
- Assurance
- Engineering
- Declared partition coverage
- PASS · 3/3 declared partitions (w-va, va-w, invalid-domain) · Matrix
- Known limitations
- Sinusoidal PF; optional factor scales result
- Core CVP does not include live graph, viewport, or pointer interaction.
- Model
- Apparent power in VA from real power in watts and PF, or watts from VA and PF.
- Scope
- PF in (0, 1] — required (not optional)
- Verification
- Engine tested · Source checked · v1.3.1 · CVP VERIFIED · CVP protocol 1.0.0-proposed · Engineering assurance· View Manifest · CVP overview · Specification
- Versions
- Calculation 1.3.1 · CVP protocol 1.0.0-proposed
- CVP identity
- 5/5 property · digest c927268aa5e1
- Legacy regression
- 16/16 tests · Production surface contract 4/4
- Trust layers
- Verification VERIFIED · Production CURRENT · overall VERIFIED
- Reference
- O1 model · O2 expected_values · O2 numerical_behavior
- Interfaces
- PASS · UI (SSR) / REST / MCP
- Supplemental domain review
- Not performed
- Named expert review
- Not performed
- CVP suite
- 2/2 golden · 2/2 CVP boundary · 2/2 invalid · 5/5 property · 1/1 cross-interface · 4/4 CVP contract · Manifest
- Sources
- IEC 60050 — International Electrotechnical Vocabulary
- IEC 60050 — International Electrotechnical Vocabulary
- IEEE Std 1459-2025
- BIPM SI Brochure (9th edition, version 4.01)
- NIST Guide to the SI (SP 811)
- Evidence
- 9 legacy golden · 2 legacy boundary · legacy regression suite · 2/2 oracle-backed golden · 2/2 invalid · Artifact integrity PASS
- Semantic contract
- PASS
Full verification
Formulas
Core equations used by this calculator.
How to use
Choose Watts → VA or VA → Watts
Forward mode needs real power; reverse needs apparent power.
Enter power and power factor
Prefer nameplate PF. If unknown, use 0.8 for mixed loads or 0.6–0.7 for heavy motors / older gear.
Read VA or watts
Select UPS/inverter/generator VA with headroom above the calculated value.
Example calculations
Common configurations with formula and result.
1000 W · PF 0.8
Default check
UPS example
500 W · PF 0.67
Unity PF
1000 W · PF 1
VA → watts
1250 VA · PF 0.8
Inverter loads
3200 W · PF 0.8
Watts → VA for 1000 W by PF
Common values at a glance.
| Power factor | VA for 1000 W | Typical loads |
|---|---|---|
| 1.0 | 1000 VA | Heaters, incandescent |
| 0.9 | 1111 VA | Motors full load / modern PSU |
| 0.8 | 1250 VA | Mixed household / genset default |
| 0.7 | 1429 VA | Motor-heavy |
| 0.6 | 1667 VA | Computers / older UPS loads |
Watts to VA calculator specification
Version 1.3.1 · Engine tested
- Engine tested 16/16 tests · Production surface contract 4/4
- Named expert review Not performed
- Calculation version 1.3.1
- Definition
- Volt-amperes (VA) measure apparent power; watts (W) measure real power. They are linked by power factor: VA = W ÷ PF and W = VA × PF. Voltage and phase are not required once you know watts (or VA) and PF. UPS, inverters, and many generators are sized in VA — always convert watts through PF before selecting equipment.
- What it calculates
- Apparent power in VA from real power in watts and PF, or watts from VA and PF.
- Inputs
- Real power P (W) and PF → VA
- Apparent power S (VA) and PF → W
- Outputs
- VA or watts
- Formula
VA=W/PF; W=VA·PF- Assumptions
- PF in (0, 1] — required (not optional)
- No voltage/phase required once P (or S) and PF are known
- Units
- W, PF → VA
- Boundary conditions
- PF ≤ 0 or > 1 → POWER_FACTOR_OUT_OF_RANGE
- Missing PF → MISSING_REQUIRED_INPUT
- Zero watts/VA with valid PF → 0
- API: mode w-va|va-w; a|P|S; b|power_factor; optional factor
- Example
- 1000 W, PF 0.8 → 1250 VA
- Validation cases
12 published on this page · 16/16 tests · Production surface contract 4/4 · View evidence
- 1000 W, PF 0.8 → 1250 VA
- 500 W, PF 0.67 → ≈ 746.27 VA
- 1000 W, PF 1 → 1000 VA
- 1250 VA, PF 0.8 → W → 1000 W
- 2000 W, PF 0.8 (2× watts) → 2500 VA (linear in W)
- 1000 W, PF 0.4 (half PF) → 2500 VA (inverse in PF)
- 0 W, PF 0.8 → 0 VA
- 1000 W, PF 0 → error POWER_FACTOR_OUT_OF_RANGE
- 5000 W, PF 0.9 → ≈5555.56 VA
- 2500 VA, PF 0.8 → W → 2000 W
- missing PF → error MISSING_REQUIRED_INPUT
- 1000 W → VA → W round-trip at PF 0.8 → 1000 W
- Sources
- IEC 60050 — International Electrotechnical Vocabulary — Apparent power (IEV 131-11-41) · accessed 2026-09-05Supports: S (VA) is apparent power; distinct from active power P (W); unit volt-ampere (VA)
- IEC 60050 — International Electrotechnical Vocabulary — Power factor (IEV 131-11-46) · accessed 2026-09-05Supports: λ = |P| / S; S = P / λ and P = S × λ
- IEEE Std 1459-2025 — Apparent power from real power and power factor · 2025-05-16 · errata checked · accessed 2026-09-05Supports: S(VA) = P(W) / PF; P = S × PF
- BIPM SI Brochure (9th edition, version 4.01) — SI units for watt and volt-ampere · 2026-06
·
DOI
· accessed 2026-09-05Supports: W and VA unit relationships
- NIST Guide to the SI (SP 811) — Watt and volt-ampereSupports: SI power unit relationships
- IEC 60050 — International Electrotechnical Vocabulary — Apparent power (IEV 131-11-41) · accessed 2026-09-05
- Calculation version
- 1.3.1
Background
Interpretation and common distinctions.
Convert watts (real power) to volt-amperes (apparent power) using power factor (required):
S((VA)) = (P((W)))/PF P((W)) = S((VA)) × PF
Default example: 1000 W · PF 0.8 → 1250 VA.
Supported and not supported
Supported
- Watts → VA and VA → watts with PF in (0, 1]
- API engine
watts-va(tool idwatts-to-va); roadmap opreal_from_S_pf/apparent_from_P_pf - Capability id:
electrical.watts_to_va(model:electrical.active_power_from_apparent_power)
Not supported
- Treating VA ≈ W without PF
- Voltage/current → VA (use Amps→VA)
- Unbalanced / harmonic power (IEEE 1459 full)
Agent / API notes
Pin calculation_version: 1.3.1. Stable errors: MISSING_REQUIRED_INPUT, INVALID_NUMBER, VALUE_MUST_BE_NON_NEGATIVE, POWER_FACTOR_OUT_OF_RANGE, INVALID_MODE.
Legacy body fields a / b still work; prefer P|S and power_factor.
Watts vs VA
| Watts (W) | VA | |
|---|---|---|
| Measures | Real / active power | Apparent power |
| Use for | Energy, heat, work done | Equipment ratings, current capacity |
| Relation | P = S × PF | S = P / PF |
At PF = 1, VA equals watts. Lower PF means more VA (and more current) for the same watts.
Why convert?
- UPS / inverter / generator nameplates are often in VA or kVA
- Breakers and wire must handle current from apparent power
- Power factor correction planning starts from W vs VA
Rule of thumb for mixed loads: multiply watts by 1.25 (same as PF = 0.8).
Typical power factor
| Load | Typical PF | VA for 1000 W |
|---|---|---|
| Resistive heater / incandescent | 0.95–1.0 | ~1000–1053 VA |
| Computers / office gear | 0.6–0.8 | 1250–1667 VA |
| Induction motor (full load) | 0.8–0.9 | 1111–1250 VA |
| Induction motor (light load) | 0.2–0.7 | much higher VA |
| Mixed household (estimate) | 0.8 | 1250 VA |
Tips
- Always convert before picking VA-rated gear — a 5000 W load is not a 5000 VA inverter unless PF = 1.
- Prefer conservative PF (0.7–0.8) when the exact value is unknown.
- For kVA results: kVA = VA / 1000, or use watts to kVA.
Related tools
Other calculators in this family: Amps to kW Calculator, Amps to VA Calculator, Amps to Volts Calculator, Electric Power Calculator, Energy Consumption Calculator, Energy Cost Calculator, eV to Volts Calculator, kVA to Amps Calculator . Explore all Power & Energy.
Frequently asked questions
Key distinctions behind the calculation.
How do I convert watts to VA?
Divide real power by power factor: VA = W ÷ PF. Example: 1000 W ÷ 0.8 = 1250 VA.
How do I convert VA to watts?
Multiply: W = VA × PF. Example: 1250 VA × 0.8 = 1000 W.
What is the difference between watts and VA?
Watts are real power that does work or becomes heat. VA is apparent power (RMS volts × amps) and includes reactive power. They are equal only when PF = 1.
What power factor should I use?
Prefer nameplate or measured PF. Resistive ≈ 1; mixed household ≈ 0.8; motors often 0.6–0.9; some IT/UPS loads ≈ 0.6–0.7. When unsure, 0.8 is a common conservative estimate.
Why size UPS and inverters in VA?
They must supply apparent power — both real and reactive. A 1000 W load at PF 0.8 needs 1250 VA capacity, not a 1000 VA unit.
Do I need voltage or phase?
Not for watts ↔ VA when PF is known. Voltage matters when converting VA to amps (I ≈ VA / V for single-phase).
How is VA related to kVA?
1 kVA = 1000 VA. So kVA = W ÷ (1000 × PF). Use watts to kVA for kilovolt-amp results.
Does VA determine wire and breaker size?
Current follows apparent power. Using watts alone underestimates amps when PF < 1 — convert to VA first, then to amps.