kW to VA Calculator
Convert kilowatts to volt-amperes using power factor. Distinguishes real vs apparent power for feeder and transformer sizing. Runs locally in your browser.
Trust summary CVP VERIFIED · production STALE · CVP protocol 1.0.0-proposed · Engineering assurance
- Input interpretation
- Enter values to calculate.
- Result
- —
- Assurance
- Engineering
- Declared partition coverage
- PASS · 3/3 declared partitions (kw-va, va-kw, invalid-domain) · Matrix
- Known limitations
- Sinusoidal PF; built-in ×/÷1000
- Core CVP does not include live graph, viewport, or pointer interaction.
- Model
- Apparent power in VA from kW and PF, or real power in kW from VA and PF.
- Scope
- PF relates real and apparent power for the AC load
- Verification
- Engine tested · Source checked · v1.3.1 · CVP VERIFIED · production STALE · CVP protocol 1.0.0-proposed · Engineering assurance· View Manifest · CVP overview · Specification
- Versions
- Calculation 1.3.1 · CVP protocol 1.0.0-proposed · Evidence 2026-09-19.review-policy-l2
- Verification revision
- 2026-09-19.review-policy-l2 · 3/3 property · digest f34e338c9eda
- Legacy regression
- 14/14 tests · Production surface contract 2/2
- Trust layers
- Verification VERIFIED · Production STALE · overall VERIFIED_STALE
- CVP status
- STALE · STALE · Last attested schema matched 1.3.1 snapshot / local build · Semantic contract ✓ · Last attestation PASS · current evidence changed · re-attestation required · Public/cache ✓ · Origin ✓
- Reference
- O1 model · O2 expected_values · O2 numerical_behavior
- Interfaces
- PASS · UI (SSR) / REST / MCP
- Supplemental domain review
- Internal · Pass · electrical-engineer
- Named expert review
- Not performed
- CVP suite
- 2/2 golden · 3/3 CVP boundary · 4/4 invalid · 3/3 property · 1/1 cross-interface · 2/2 CVP contract · Manifest
- Sources
- IEC 60050 — International Electrotechnical Vocabulary
- IEC 60050 — International Electrotechnical Vocabulary
- IEEE Std 1459-2025
- BIPM SI Brochure (9th edition, version 4.01)
- NIST Guide to the SI (SP 811)
- Evidence
- 7 legacy golden · 4 legacy boundary · legacy regression suite · 2/2 oracle-backed golden · 4/4 invalid · Artifact integrity PASS · CalculatorX electrical review
- Semantic contract
- PASS
Full verification
Formulas
Core equations used by this calculator.
How to use
Choose kW → VA or VA → kW
Forward needs real power; reverse needs apparent power in VA.
Enter power and power factor
PF must be greater than 0. Prefer nameplate or measured values.
Read VA or kW
Result updates as you type. For kVA output, divide VA by 1000.
Example calculations
Common configurations with formula and result.
5 kW · PF 0.8
Common worked example
1 kW · PF 0.8
Common quick check
10 kW · PF 0.8
Larger load
Unity PF
1 kW · PF 1.0
VA → kW
6,250 VA · PF 0.8
kW to VA at PF = 0.8
Common values at a glance.
| Real power (kW) | Apparent power (VA) | kVA |
|---|---|---|
| 1 | 1,250 | 1.25 |
| 5 | 6,250 | 6.25 |
| 7.5 | 9,375 | 9.375 |
| 10 | 12,500 | 12.5 |
| 15 | 18,750 | 18.75 |
| 20 | 25,000 | 25 |
| 25 | 31,250 | 31.25 |
| 50 | 62,500 | 62.5 |
| 75 | 93,750 | 93.75 |
| 100 | 125,000 | 125 |
kW to VA calculator specification
Version 1.3.1 · Engine tested · Supplemental domain review · Internal · 2026-08-08
- Engine tested 14/14 tests · Production surface contract 2/2
- Supplemental domain review Internal · Pass · electrical-engineer · 2026-08-08
- Named expert review Not performed
- Calculation version 1.3.1
Review policy · Evidence · Reviewed by CalculatorX electrical review (electrical-engineer)
- Definition
- Kilowatts (kW) measure real power; volt-amperes (VA) measure apparent power. Converting between them requires power factor: VA = 1000 × kW ÷ PF. At PF = 1, 1 kW = 1000 VA. This tool also reverses the conversion (VA → kW).
- What it calculates
- Apparent power in VA from kW and PF, or real power in kW from VA and PF.
- Inputs
- Real power P (kW) or apparent power S (VA)
- Power factor PF (0–1)
- Outputs
- Apparent power in VA
- Real power in kW
- Formula
S(VA)=1000·P(kW)/PF; P=S·PF/1000- Assumptions
- PF relates real and apparent power for the AC load
- 1 kW = 1000 W
- Units
- kW, PF → VA
- Boundary conditions
- power_factor must be in (0, 1] — PF≤0 → FRACTION_OUT_OF_RANGE (engine kw-va)
- Missing PF → MISSING_REQUIRED_INPUT
- Built-in ×1000 between kW and VA
- Example
- 5 kW, PF 0.8 → 6,250 VA
- Validation cases
13 published on this page · 14/14 tests · Production surface contract 2/2 · View evidence
- 5 kW, PF 0.8 → 6250 VA
- 1 kW, PF 0.8 → 1250 VA
- 10 kW, PF 0.8 → 12500 VA
- 1 kW, PF 1 → 1000 VA
- 10 kW, PF 0.8 (2× of 5 kW) → 12500 VA (linear in kW)
- 5 kW, PF 0.4 (half PF) → 12500 VA (inverse in PF)
- 6250 VA, PF 0.8 → kW → 5 kW
- 5 kW, PF 0 → VA → 0 VA (soft: PF=0 on quotient → 0)
- 0 kW, PF 0.8 → 0 VA
- 2 kW, PF 0.5 → 4000 VA
- 0 VA, PF 0.8 → kW → 0 kW
- 6250 VA, PF 0 → kW → 0 kW
- 5 kW → VA → kW round-trip at PF 0.8 → 5 kW
- Sources
- IEC 60050 — International Electrotechnical Vocabulary — Apparent power (IEV 131-11-41) · accessed 2026-09-05Supports: S (VA) is apparent power; distinct from active power P (kW); unit volt-ampere (VA)
- IEC 60050 — International Electrotechnical Vocabulary — Power factor (IEV 131-11-46) · accessed 2026-09-05Supports: λ = |P| / S; S(VA) = 1000 × P(kW) / λ and P = S × λ / 1000
- IEEE Std 1459-2025 — Real and apparent power conversion · 2025-05-16 · errata checked · accessed 2026-09-05Supports: S(VA) = 1000 × P(kW) / PF; P = S × PF / 1000
- BIPM SI Brochure (9th edition, version 4.01) — SI units for watt and volt-ampere · 2026-06
·
DOI
· accessed 2026-09-05Supports: 1 kW = 1000 W scaling in VA conversion
- NIST Guide to the SI (SP 811) — Watt and volt-ampere as power unitsSupports: 1 kW = 1000 W scaling in VA conversion
- IEC 60050 — International Electrotechnical Vocabulary — Apparent power (IEV 131-11-41) · accessed 2026-09-05
- Last reviewed
- 2026-08-08
- Reviewed by
- CalculatorX electrical review (electrical-engineer)
- Calculation version
- 1.3.1
Background
Interpretation and common distinctions.
Convert kilowatts (kW) to volt-amps (VA) using power factor:
S((VA)) = (1000 × P((kW)))/PF
Default example: 5 kW at PF 0.8 → 6,250 VA.
kW vs VA
| Quantity | Unit | Meaning |
|---|---|---|
| Real power | kW | Power that does work or becomes heat (1 kW = 1000 W) |
| Apparent power | VA | Voltage × current at the supply, before applying PF |
| Power factor | PF | PF = (kW × 1000) / VA, typically 0–1 |
Apparent power is what sizing of transformers, UPS, and wiring often follows; real power is what does useful work. Reactive elements make them differ unless PF ≈ 1.
Common values at PF 0.8
| kW | VA |
|---|---|
| 1 | 1,250 |
| 5 | 6,250 |
| 10 | 12,500 |
| 100 | 125,000 |
Typical power factors
| Load | Typical PF |
|---|---|
| Resistive heater / incandescent | ≈ 1.0 |
| Many motors / genset ratings | 0.8–0.9 |
| Lightly loaded induction motor | can be much lower |
Prefer nameplate or measured PF when sizing equipment.
Related tools
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Frequently asked questions
Key distinctions behind the calculation.
How do I convert kW to VA?
Use VA = (kW × 1000) ÷ PF. Example: 5 kW at PF 0.8 → 1000 × 5 ÷ 0.8 = 6,250 VA.
Why is power factor required?
kW is real power; VA is apparent power. They differ when the load is inductive or capacitive. PF = real ÷ apparent bridges the two.
What if PF = 1?
Then VA = 1000 × kW. One kilowatt equals 1,000 volt-amps at unity power factor.
How is this different from kW to kVA?
Same idea, different scale: kVA = kW ÷ PF, while VA = 1000 × kW ÷ PF. 1 kVA = 1000 VA. Use kVA to kW when you prefer kilovolt-amp results.
What PF should I enter?
Use the equipment nameplate or a measured value when possible. Many motors and gensets are around 0.8–0.9; resistive heaters are near 1.0.
How do I convert VA back to kW?
kW = VA × PF ÷ 1000. Example: 6,250 VA × 0.8 ÷ 1000 = 5 kW.
Do I need voltage or phase?
Not for this conversion. Voltage and phase are needed when you start from amps instead of kW or VA.