Watts to Volts Calculator
Find voltage from power and current (or resistance). Useful for DC and resistive AC checks with unit guidance. Runs locally in your browser.
Trust summary Engine tested · Source checked · v1.3.1
- Input interpretation
- Enter values to calculate.
- Result
- —
- Model
- Voltage from watts and amps (DC/1φ/3φ) or from watts and ohms; watts from volts and amps.
- Scope
- RMS quantities for AC
- Verification
- Engine tested · Source checked · v1.3.1
- Named expert review
- Optional · Not performed
- Sources
- Watt’s law / power identity
- Resistive power identity
- IEC 60050 — International Electrotechnical Vocabulary
- IEC 60050 — International Electrotechnical Vocabulary
- IEEE Std 1459-2025
- BIPM SI Brochure (9th edition, version 4.01)
- NIST Guide to the SI (SP 811)
Formulas
Core equations used by this calculator.
How to use
Choose path
W → V (amps) for power and current; W → V (ohms) for power and resistance; V → W to reverse.
Enter values and circuit type
For AC with amps, set PF and single/three phase. For DC, PF = 1 and single phase.
Read volts or watts
Three-phase amps path returns line-to-line voltage.
Example calculations
Common configurations with formula and result.
DC · 20 W · 4 A
V = P ÷ I
240 W · 2 A
Default DC check
AC 1φ · 1300 W · 12 A · PF 0.9
With power factor
From resistance
40 W · 10 Ω
RF · 100 mW · 50 Ω
Enter 0.1 W
Volts → watts
120 V · 2 A · PF 1
Quick V = P ÷ I (PF = 1)
Common values at a glance.
| Power | Current | Voltage |
|---|---|---|
| 20 W | 4 A | 5 V |
| 60 W | 5 A | 12 V |
| 120 W | 10 A | 12 V |
| 240 W | 2 A | 120 V |
| 1000 W | 8.333 A | 120 V |
| 40 W · 10 Ω | — | 20 V (√ path) |
Watts to Volts calculator specification
Version 1.3.1 · Engine tested
- Engine tested 15 published cases
- Named expert review Not performed
- Calculation version 1.3.1
- Definition
- You cannot convert watts to volts from power alone — you also need current (amps) or resistance/impedance (ohms). With current: DC V = P/I; AC 1φ V = P/(I×PF); AC 3φ L-L V = P/(√3×I×PF). With resistance: V = √(P×R). This tool also reverses volts × current → watts.
- What it calculates
- Voltage from watts and amps (DC/1φ/3φ) or from watts and ohms; watts from volts and amps.
- Inputs
- Power P (W) and current I (A), optional PF and phase → V
- Power P (W) and resistance R (Ω) → V
- Voltage V and current I, optional PF and phase → W
- Outputs
- Voltage in V, or power in W
- Formula
V=P/(√3 (3φ only)·I·PF); V=√(P·R); P=√3 (3φ only)·V·I·PF- Assumptions
- RMS quantities for AC
- Balanced three-phase when √3 selected
- Ohms path assumes real resistive (or |Z| for RF magnitude)
- Units
- W, A, PF → V
- W, Ω → V
- Boundary conditions
- Amps path (phase-quotient): zero current (b) → 0 V — soft
- Zero power (a) on amps path → 0 V
- PF ≤ 0 on amps/reverse watts paths treated as PF = 1 (engine: pf > 0 ? pf : 1) — soft
- Ohms path (sqrt-product): negative P×R clamped to 0 under √ — soft
- Zero P or R on ohms path → 0 V
- Engine does not hard-reject PF outside (0,1]; document PF ∈ (0,1] for physical AC use
- Example
- 240 W, 2 A, PF 1 → 120 V
- Validation cases
15 published on this page
- 20 W, 4 A, DC → 5 V
- 240 W, 2 A, PF 1, 1φ → 120 V
- 1300 W, 12 A, PF 0.9, 1φ → ≈120.37 V
- 40 W, 10 Ω → 20 V
- 0.1 W, 50 Ω → ≈2.236 V
- 120 V, 2 A, PF 1 → W → 240 W
- 1000 W, 10 A, PF 0.8, 3φ → ≈72.17 V
- 480 W, 2 A, PF 1 (2× P) → 240 V (linear in P)
- 240 W, 1 A, PF 1 (half I) → 240 V (inverse in I)
- 240 W, 0 A, PF 1 → 0 V (soft: zero current → 0)
- 0 W, 2 A, PF 1 → 0 V
- 240 W, 2 A, PF 0 → 120 V (soft: PF≤0 treated as 1)
- -10 W, 10 Ω → 0 V (soft: negative P×R → √0)
- 0 W, 10 Ω → 0 V
- 240 W → 120 V → W round-trip at PF 1 → 240 W
- Sources
- Watt’s law / power identity — Real power P = V × I × PF (1φ); P = √3 × V × I × PF (3φ L-L)Supports: V = P/(I·PF); P = V·I·PF; 3φ with √3
- Resistive power identity — P = V²/R ⇒ V = √(P·R)Supports: W → V (ohms) / RF |Z| magnitude path
- IEC 60050 — International Electrotechnical Vocabulary — Active power (IEV 131-11-42) · accessed 2026-09-05Supports: P is active power; unit watt (W). Watts-path voltage uses P, not apparent power S.
- IEC 60050 — International Electrotechnical Vocabulary — Power factor (IEV 131-11-46) · accessed 2026-09-05Supports: λ = |P| / S; AC watts path V = P / (I·λ) (1φ) or V = P / (√3·I·λ) (3φ L-L)
- IEEE Std 1459-2025 — Power factor in AC real-power calculations · 2025-05-16 · errata checked · accessed 2026-09-05Supports: PF scaling on amps and reverse watts paths
- BIPM SI Brochure (9th edition, version 4.01) — SI units for ampere, volt, ohm, and watt · 2026-06
·
DOI
· accessed 2026-09-05Supports: DC V = P/I; V = √(P·R) from P = V²/R
- NIST Guide to the SI (SP 811) — Volt, ampere, ohm, wattSupports: SI unit relationships for V, A, Ω, W
- Watt’s law / power identity — Real power P = V × I × PF (1φ); P = √3 × V × I × PF (3φ L-L)
- Calculation version
- 1.3.1
Background
Interpretation and common distinctions.
Convert watts to volts using current or resistance. Power alone is not enough.
Default (amps path): 240 W ÷ 2 A = 120 V.
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Frequently asked questions
Key distinctions behind the calculation.
How do I convert watts to volts?
Divide power by current: V = P ÷ I for DC. For AC single-phase use V = P ÷ (I × PF). For three-phase line-to-line use V = P ÷ (√3 × I × PF). Or if you know resistance: V = √(P × R).
Can I convert watts to volts without amps?
Not with the amps formula. You need either current or resistance/impedance. Watts alone are not enough.
How do I handle AC power factor?
Use the W → V (amps) tab, set PF, and choose single or three phase. Resistive loads: PF = 1.
What about three-phase?
Select three phase on the amps tab. The result is line-to-line RMS voltage. Line-to-neutral: V = P ÷ (3 × I × PF).
When do I use the ohms formula?
When you know power and resistance (or characteristic impedance Z). V = √(P × R). Common for resistive heaters and RF systems (e.g. 50 Ω).
How do I convert volts back to watts?
Use V → W: P = V × I for DC; multiply by PF (and √3 for 3φ) for AC real power.
Is milliwatt RF supported?
Yes on the ohms tab — convert mW to watts first (100 mW = 0.1 W). Example: √(0.1 × 50) ≈ 2.236 V.